Question

The conductivity of 0·001 mol L–1 solution of acetic acid is 3·905 × 10–5 S cm–1. Calculate its molar conductivity. If Λ°m for acetic acid is 390·5 S cm2 mol–1, then calculate its degree of dissociation (α).

Assertion (A): Electrolysis of aqueous solution of NaCl gives chlorine gas at anode instead of oxygen gas. Reason (R): Formation of oxygen gas at anode requires overpotential.

Calculate the emf of the following cell at 25°C: Zn (s) | Zn²⁺ (0.1 M) || H⁺ (0.01 M) | H₂ (g) (1 bar), Pt (s) [Given: E°(Zn²⁺/Zn) = – 0.76 V, E°(H⁺/H₂) = 0.00 V, log 10 = 1]

State Kohlrausch law of independent migration of ions. Why does the conductivity of a solution decrease with dilution?