∫₀² √(4 − x²) dx equals :

Question

MCQ (Single)Definite Integral as Limit of a SumArea Enclosed by Circle Using IntegrationCBSE PYQ

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Evaluate : ∫ from 0 to π/2 sin 2x cos 3x dx

Given d/dx F(x) = 1/√(2x – x²) and F(1) = 0, find F(x).

Definite Integral as Limit of a Sum

The value of ∫₋₁¹ x|x| dx is :

The value of ∫(π/4 to π/2) cot θ cosec² θ dθ is :

If ∫₋₂³ x² dx = k∫₀² x² dx + ∫₂³ x² dx, then the value of k is :

∫₀^(π/6) sec²(x − π/6) dx is equal to :