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Direction ratios of a vector parallel to line (x–1)/2 = – y = (2z+1)/6 are :
The position vectors of vertices of △ ABC are A(2î – ĵ + k̂), B(î – 3ĵ – 5k̂) and C(3î – 4ĵ – 4k̂). Find all the angles of △ ABC.
The lines (1–x)/2 = (y–1)/3 = z/1 and (2x–3)/2p = y/(–1) = (z–4)/7 are perpendicular to each other for p equal to:
Assertion (A) : A line through the points (4, 7, 8) and (2, 3, 4) is parallel to a line through the points (−1, −2, 1) and (1, 2, 5). Reason (R) : Lines r→ = a₁→ + λb₁→ and r→ = a₂→ + μb₂→ are parallel if b₁→ · b₂→ = 0.
Find the angle between the lines 2x = 3y = -z and 6x = -y = -4z.
The angle between the lines 2x = 3y = −z and 6x = −y = −4z is
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