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Direction ratios of a vector parallel to line (x–1)/2 = – y = (2z+1)/6 are :
The position vectors of vertices of △ ABC are A(2î – ĵ + k̂), B(î – 3ĵ – 5k̂) and C(3î – 4ĵ – 4k̂). Find all the angles of △ ABC.
Find the equation of the line which bisects the line segment joining points A(2, 3, 4) and B(4, 5, 8) and is perpendicular to the lines (x–8)/3 = (y+19)/(–16) = (z–10)/7 and (x–15)/3 = (y–29)/8 = (z–5)/(–5).
The direction ratios of the line (x – 1)/3 = (2 – y)/1 = 3z/2 are :
Find the angle between the lines (5 – x)/(–7) = (y + 2)/(–5) = z/1 and x/1 = y/2 = z/3.
The value of λ for which the angle between the lines r→ = î + ĵ + k̂ + p(2î + ĵ + 2k̂) and r→ = (1 + q)î + (1 + qλ)ĵ + (1 + q)k̂ is π/2 is :
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