Prove that (sin θ – cos θ + 1)/(sin θ + cos θ – 1) = 1/(sec θ – tan θ), using the identity sec²θ = 1 + tan²θ.

Free previous-year papers & practice for JEE, NEET and CBSE Boards.

Free previous-year papers & practice for JEE, NEET and CBSE Boards.

Reciprocal and Quotient Relations of Trigonometric Ratios, Identity Relating Secant and Tangent | PadhAiPro

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TextReciprocal and Quotient Relations of Trigonometric RatiosIdentity Relating Secant and Tangent

If sec θ − tan θ = m, then the value of sec θ + tan θ is :

Prove that : tan θ/(1 − cot θ) + cot θ/(1 − tan θ) = 1 + sec θ cosec θ

Pythagorean Trigonometric Identity

In a right triangle ABC, right-angled at A, if sin B = 1/4, then the value of sec B is

If a sec θ + b tan θ = m and b sec θ + a tan θ = n, prove that a² + n² = b² + m²

Use the identity : sin²A + cos²A = 1 to prove that tan²A + 1 = sec²A. Hence, find the value of tan A, when sec A = 5/3, where A is an acute angle.

Prove that : (cos θ – 2 cos³θ)/(sin θ – 2 sin³θ) + cot θ = 0.