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Prove that : tan θ/(1 − cot θ) + cot θ/(1 − tan θ) = 1 + sec θ cosec θ
In a right triangle ABC, right-angled at A, if sin B = 1/4, then the value of sec B is
It is given that sin (A − B) = sin A cos B − cos A sin B. Use it to find the value of sin 15°.
If sin A = y, then express cos A and tan A in terms of y.
sec A = 2 cos A is true for A =
(cot θ + tan θ) equals :
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