Calculate the emf of the following cell at 298K. Cu / Cu2+ (0.025M) // Ag+ (0.005M) / Ag Given E°Cu2+/Cu = 0.34V, E°Ag+/Ag = 0.80V, 1 Faraday = 96500 C mol-1

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NumericalEMF of a Galvanic CellNernst Equation for Electrode and Cell Potential

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Calculate the e.m.f. of the following cell at 298K : Fe(s) | Fe²⁺ (0.001 M) || H⁺ (0.01M) | H₂(g) (1 bar) | Pt(s) Given that E°cell = +0.44 V [log 2 = 0.3010 log 3 = 0.4771 log 10 = 1]

TextEMF of a Galvanic CellNernst Equation for Electrode and Cell Potential

Calculate the emf of the following cell at 25°C: Zn (s) | Zn²⁺ (0.1 M) || H⁺ (0.01 M) | H₂ (g) (1 bar), Pt (s) [Given: E°(Zn²⁺/Zn) = – 0.76 V, E°(H⁺/H₂) = 0.00 V, log 10 = 1]

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